Apple

Le 23/02/2015 à 23:08, S. J. Cunningham <email@hidden> a écrit :

How can I get list_4 to be {file1,file2,file3} in the below example?

(I know I can just use set list_4 to list_3 or copy list_3 to list_4 but that doesn't work if I just want to extract parts of list_3 for example)

tell application "Finder"
set list_1 to {1, 2, 3, 4, 5}
set list_2 to {}
repeat with nn in list_1
set list_2 to list_2 & nn
end repeat
--> list_2 = {1,2,3,4,5} -- Yes!

set list_3 to files of folder someolder
--> list_3 = {file 1,file 2, file 3}

set list_4 to {}
repeat with nn in list_3
set list_4 to list_4 & {nn}
end repeat

--> list_4 = {item 1 of {file 1,file 2, file 3}, item 2 of {file 1,file 2, file 3}, item 3 of {file 1,file 2, file 3}} -- NO!

-- This works but it's ugly

set list_4 to {}
repeat with nn from 1 to (count of list_3)
set list_4 to list_4 & {item nn of list_3}
end repeat

--> list_4 = {file 1,file 2, file 3}

end tell

You may try :

set someFolder to ((path to desktop as text) & "a folder:") as alias

set list_1 to {1, 2, 3, 4, 5}

set list_2 to {}

repeat with nn in list_1

set list_2 to list_2 & nn

end repeat

--> list_2 = {1,2,3,4,5} -- Yes!

tell application "Finder"

set list_3 to files of folder someFolder

--> list_3 = {file 1,file 2, file 3}

set list_4 to {}

repeat with nn in list_3

set list_4 to list_4 & {contents of nn}

end repeat

--> list_4 = {item 1 of {file 1,file 2, file 3}, item 2 of {file 1,file 2, file 3}, item 3 of {file 1,file 2, file 3}} -- NO!

-- This works but it's ugly

set list_4 to {}

repeat with nn from 1 to (count of list_3)

set list_4 to list_4 & {item nn of list_3}

end repeat

--> list_4 = {file 1,file 2, file 3}

end tell

Yvan KOENIG (VALLAURIS, France) lundi 23 février 2015 23:21:57

References:
	>Finder Scripting Qusetion (From: "S. J. Cunningham" <email@hidden>)