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Strip substring using do shell script and regex
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Strip substring using do shell script and regex


  • Subject: Strip substring using do shell script and regex
  • From: debt <email@hidden>
  • Date: Wed, 28 Dec 2016 07:52:55 -0800

I’m trying to strip a substring of 2 digits following an asterisk (e.g. *67 or *82, etc.) but I’m running into problems.  Can someone see what I’m doing wrong here?

set clean_text to do shell script "echo " & quoted form of original_name & " | perl -pe ’s/\*\d{2}//g;'"

The regex works fine in Perl, so I’m not sure what’s wrong with the above.

Thanks,
Marc
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