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Re: Position of an element in a list
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Re: Position of an element in a list


  • Subject: Re: Position of an element in a list
  • From: Jim Underwood <email@hidden>
  • Date: Thu, 3 Aug 2017 00:13:06 +0000
  • Thread-topic: Position of an element in a list

Shane, I must be doing something wrong.
When I change the script to use your below statement, I get this error:
________________________________
"two" doesn’t understand the “lowercaseString” message.
________________________________
Running Script Debugger 6.0.5 (6A205) on macOS 10.11.6.

The modified script:

________________________________

use AppleScript version "2.5" # requires El Capitan or higher

use framework "Foundation"

use scripting additions


on indexOf:aValue inList:theList listType:listType



  local |⌘|, theArray, theIndex # useful for Script Debugger



  set |⌘| to current application

  set theArray to |⌘|'s NSArray's arrayWithArray:theList



  if (listType = "string") then

    (*

         PER SHANE, if the entire list is text/strings, then you can use this
instead

          to make it Case Insensitive

    *)

    set theIndex to (theArray's valueForKey:"lowercaseString")'s
indexOfObject:(aValue's lowercaseString())



  else



    --- VALID for ALL Data Types, but is CASE SENSITIVE for Text ---

    set theIndex to theArray's indexOfObject:aValue



  end if



  if theIndex = |⌘|'s NSNotFound then

    return 0

  else

    return (theIndex + 1) # +1 because ASObjC counts starting from 0

  end if

end indexOf:inList:listType:



set allStrList to {"one", "TWO", "Three"}

log (its indexOf:"two" inList:allStrList listType:"string")

________________________________


Best Regards,

Jim Underwood
aka JMichaelTX


From: AppleScript-Users
<applescript-users-bounces+jmichael=email@hidden<mailto:applescript-users-bounces+jmichael=email@hidden>>
 on behalf of Shane Stanley
<email@hidden<mailto:email@hidden>>
Date: Wednesday, August 2, 2017 at 6:35 PM
To: "ASUL (AppleScript)"
<email@hidden<mailto:email@hidden>>
Subject: Re: Position of an element in a list

On 3 Aug 2017, at 8:45 am, Nigel Garvey
<email@hidden<mailto:email@hidden>> wrote:

the version here seems a bit perverse

But in a very attractive way :-)

It could be good for long lists, although in practice they tend to consist of
items of the same class, in which case you can also use:

set theIndex to (theArray's valueForKey:"lowercaseString")'s
indexOfObject:(aValue's lowercaseString())

Obviously that fails if the list items aren't all strings.

--
Shane Stanley <email@hidden<mailto:email@hidden>>
<www.macosxautomation.com/applescript/apps/<http://www.macosxautomation.com/applescript/apps/>>,
 <latenightsw.com<http://latenightsw.com>>


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  • Follow-Ups:
    • Re: Position of an element in a list
      • From: Shane Stanley <email@hidden>
References: 
 >Re: Position of an element in a list (From: "Nigel Garvey" <email@hidden>)
 >Re: Position of an element in a list (From: Shane Stanley <email@hidden>)

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