Re: Strings
Re: Strings
- Subject: Re: Strings
- From: Sherm Pendley <email@hidden>
- Date: Tue, 12 Feb 2002 20:04:09 -0500
char input[258], output[258], *increment;
int index;
*input = [inputField stringValue]; //warning #1: assignment makes
integer
//from pointer without a cast
stringValue: returns an NSString object, not a C string. Also note that,
in C, an array *is* a pointer - a string is just a null-terminated array
of chars. Thus, when you use "*input" above, you're dereferencing the
pointer "input" and trying to store the results of the stringValue call
in the first element of the array "input[]". (That's what the "makes
integer from pointer" message is referring to.)
To get a C string, you want to do something like this:
input = [[inputField stringValue] cString];
if ( strlen( input ) <= 256 ) {
increment = &input[0];
index = 0;
while (*increment++) {
if ( input[index] != ' ' ) {
output[index] = input[index];
}
else {
output[index] = '\n';
}
index += 1;
}
output[index] = '\0';
[parsedField insertText:output]; //warning #2: passing arg 1 of
'insertText:'
//from incompatible pointer type
Same here, but the other way 'round. You're passing insertText: a C
string, when it wants an NSString. Unlike above, you're correctly
referring to "output" as a pointer, hence the error message about
"incompatible pointer type." While it *is* a pointer, "output" is a
pointer to char, not to NSString.
What you want is something more like this:
[parsedField insertText: [NSString stringWithCString: output]];
}
else {
[parsedField setStringValue:@"Error: input exceeded 256
characters."];
}
OR, you could do it all in Objective-C, like this, and avoid all the
fixed-sized character buffers above - and their potential for buffer
overruns if someone enters too much text.
NSString *inValue = [inputField stringValue];
NSArray *ta = [inValue componentsSeparatedByString: @" "]];
NSString *outValue = [ta componentsJoinedByString: @"\n"]
[parsedField insertText: outValue];
Hope this helps!
sherm--
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| References: | |
| | >Strings (From: Daniel Byer <email@hidden>) |