Re: NSURL question (easy (i think))
Re: NSURL question (easy (i think))
- Subject: Re: NSURL question (easy (i think))
- From: Sherm Pendley <email@hidden>
- Date: Wed, 29 May 2002 19:36:17 -0400
On Wednesday, May 29, 2002, at 06:23 PM, Mamdouh wrote:
NSString *MyUrlString= [MyTextView string];
[[NSWorkspace sharedWorkspace] openURL:[NSURL
URLWithString:@"http://www.%@.com",MyUrlString]];
You can probably guess that i4m trying to replace the %@ with the
MyUrlString, but i4m making somekind of typo here, or using a wrong
method, but i cant find out what...
It looks like you're confusing URL escapes with printf-style format
strings. Easy mistake to make, as they both use %'s. The URLWithString
method processes URL escapes, but it doesn't do string formatting.
What you want is something more like this:
NSString *MyURLString = [NSString stringWithFormat:
@"
http://www.%@.com";, [MyTextView string]];
[[NSWorkspace sharedWorkspace] openURL: [NSURL URLWithString:
MyURLString]];
Hint: The words "WithFormat" in the method name imply that a method
accepts a list of parameters, and will do printf-style formatting.
Likewise, the words "WithString" imply that the method wants one
ordinary, non-formatted string. Many Cocoa methods follow similar
patterns, using "WithFoo" to help indicate the type of parameter to pass.
sherm--
Never put off until tomorrow what you can do today. There might be a law
against it by that time.
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