Re: Absolute Value |x - y|
Re: Absolute Value |x - y|
- Subject: Re: Absolute Value |x - y|
- From: Frederick Cheung <email@hidden>
- Date: Sun, 5 Dec 2004 03:11:11 +0000
On 4 Dec 2004, at 20:56, Gregory Weston wrote:
On Dec 4, 2004, at 2:18 PM, Malte wrote:
i've been looking around trying to find a method that calculates the
|absolute value| of a number.
Without success.
Does anyone know if such a function exists?
They do, but you're probably better off just writing
T abs = ((x<y) ? (y-x) : (x-y));
where T is whatever type you need the result to be.
The difference is probably that fabs has well defined behaviour in case
one (or both) of x and y is something like NaN or +/- \infty, whereas
this might not be the case for the expression you give.
Fred
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