Re: array problem
Re: array problem
- Subject: Re: array problem
- From: Dave Rosborough <email@hidden>
- Date: Thu, 11 Mar 2004 07:07:11 -0800
Basically, the problem is that you need to declare your "temp" array
inside the loop - that way you'll make a new one each time through the
loop. You don't really want "temp" to be an instance variable, either!
(I'm assuming both arrays are declared in your header file, right?)
Try this:
- (void)makeMatrix
{
int i, j;
matrixArray = [[NSMutableArray array] retain];
for(i=0; i<x; i++) // x is an int between 3 and 5
{
NSMutableArray *temp = [NSMutableArray array]; // this will create a
new array for each time through the loop, which is then
// placed in matrixArray. Also, notice that I'm not
"retaining" it - matrixArray
// will do that for me when I put temp into it.
for(j=0; j<x; j++) // x is an int between 3 and 5
{
[temp addObject:[NSNumber numberWithInt:0]];
}
[matrixArray addObject:temp];
}
}
On 11-Mar-04, at 4:47 AM, Sascha Kuehn wrote:
hi,
i have a problem with creating an array of arrays
this is my code:
-----------------------------------------------------------------------
-
-
- (void)makeMatrix
{
int i, j;
matrixArray = [[NSMutableArray array] retain];
temp = [[NSMutableArray array] retain];
for(i=0; i<x; i++) // x is an int between 3 and 5
{
for(j=0; j<x; j++) // x is an int between 3 and 5
{
[temp addObject:[NSNumber numberWithInt:0]];
}
[matrixArray addObject:temp];
}
[temp release];
}
-----------------------------------------------------------------------
-
-
what i need is an array of arrays with numbers.
in case of x = 3 like this: {{0, 0, 0}, {0, 0, 0}, {0, 0, 0}}
in case of x = 4 like this: {{0, 0, 0, 0}, {0, 0, 0, 0}, {0, 0, 0, 0},
{0, 0, 0, 0}}
in case of x = 5 like this: {{0, 0, 0, 0, 0}, {0, 0, 0, 0, 0}, {0, 0,
0, 0, 0}, {0, 0, 0, 0, 0}, {0, 0, 0, 0, 0}}
and so on.
but my method don't do that :(
sascha
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