Re: Subclassing an object's creation method (NSBezierPath's +bezierPath)
Re: Subclassing an object's creation method (NSBezierPath's +bezierPath)
- Subject: Re: Subclassing an object's creation method (NSBezierPath's +bezierPath)
- From: Prachi Gauriar <email@hidden>
- Date: Mon, 31 May 2004 17:22:38 -0500
On Monday, May 31, 2004, at 04:13PM, Steve Sims <email@hidden> wrote:
>
On 28 May 2004, at 04:47, Peter Maurer wrote:
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>> + (MyBez *)bezierPath
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>> {
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>> MyBez *path = [[self alloc] init] autorelease];
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>>
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>> [path setXLoc:0]; // only if you didn't do this in your init method
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>> [path setYLoc:0]; // only if you didn't do this in your init method
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>>
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>> return path;
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>> }
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>
>
> ... is the correct (and more elegant) way of doing this, IMHO. Cheers,
>
>
(Quick note - there's a missing '[' above...)
>
>
Sure enough doing things this way works fine and I don't get an error.
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However I'm slightly troubled by not using NSBezierPath's bezierPath
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method to create the path object, since that is the documented way to
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get an NSBezierPath object. It's possible that bezierPath does
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something that the init call does not...
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>
I therefore ended up replacing the MyBez *path line with this:
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MyBez *path = (MyBez *)[super bezierPath];
According to the documentation, you can use init to create a new empty NSBezierPath, so I wouldn't worry:
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You can create an instance of NSBezierPath using the Java constructor or
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any of the class methods bezierPath, bezierPathWithRect:, or
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bezierPathWithOvalInRect:. bezierPath initializes a new bezier-path object
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with an empty path, bezierPathWithRect: creates a path with the specified
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rectangle, and bezierPathWithOvalInRect: creates an oval path inscribed
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within a specified rectangle. In Objective-C, you can also allocate memory
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for a new instance of NSBezierPath and use the default initializer, init, to
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initialize it to an empty path.
I would use the init method, since it probably initializes your xLoc and yLoc to 0.
Moral of the story: just because class documentation doesn't list init doesn't mean you shouldn't use it.
-Prachi
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