Re: #define issues
Re: #define issues
- Subject: Re: #define issues
- From: Aaron Boothello <email@hidden>
- Date: Sat, 16 Apr 2005 18:58:01 +0800
Hmmm
tried it, didnt work.
The actual code is as follows:
typedef double matrix[16];
#define SET_ENTRY(m,r,c,e) (m[r*4+c] = e)
the 'macro' is called as follows (example):
SET_ENTRY(ret,1,1,4.5); //where ret is of type matrix
error generated is:incompatible types in assignment.
-Aaron
On Saturday, April 16, 2005, at 05:11PM, Justin Spahr-Summers <email@hidden> wrote:
>Perhaps it's your typedef line? Maybe you meant
>
>typedef double[16] matrix;
>
>I'm not even sure if that will work.
>
>On 4/16/05, Aaron Boothello <email@hidden> wrote:
>> Well yeah....
>> the code looks like that. it's not exactly what i typed in....it does the calculating of the rows and columns just fine. It's actually making the assignment. 'value' is a double and the elements in matrix are doubles. But i keep getting 'incompatible types in assignments'...
>>
>> (and it seems like the error is in "matrix[whatever] = value" for some reason)
>> i cant seem to figure if it's a syntax error or what ? how would you set a value in a #define ?
>>
>> Cheers,
>> Aaron.
>>
>> On Saturday, April 16, 2005, at 04:25PM, p3consulting <email@hidden> wrote:
>>
>> >>
>> >> #define setvalue(matrix, row, col, value) ( matrix[row+col] = value)
>> >> //roughly looks like this
>> >>
>> >
>> >row + col ?
>> >
>> >0 + 3 = 3 + 0
>> >
>> >and obviously is not what you want...
>> >
>> >((row * 4) + col)
>> >((0 * 4) + 3) == 3 and ((3 * 4) + 0) == 12
>> >
>> >+
>> >
>> >row and col being indices in an array
>> >should be int not double...
>> >
>> >
>> >(#define are not a good idea for this kind of application..., just an
>> >opinion)
>> >
>> >
>> >Pascal Pochet
>> >email@hidden
>> >----------------------------------
>> >PGP
>> >KeyID: 0x208C5DBF
>> >Fingerprint: 9BFB 245C 5BFE 7F1D 64B7 C473 ABB3 4E83 208C 5DBF
>> >
>> >
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