Re: Strange issue when converting from hex to float
Re: Strange issue when converting from hex to float
- Subject: Re: Strange issue when converting from hex to float
- From: Ian was here <email@hidden>
- Date: Fri, 22 Jul 2005 10:00:01 -0700 (PDT)
I've tried all that before, and the result always
yields zero.
float fBlue = (float)alphaComp / (float)255.0;
float fBlue = (float)alphaComp / 255.0f;
float fBlue = (float)alphaComp / 255.0L;
Thanks for trying.
--- Sherm Pendley <email@hidden> wrote:
> On Jul 22, 2005, at 11:36 AM, Ian was here wrote:
>
> > Here's a copy of the offending method...thanks for
> > offering to take a look.
>
> This was explained several times now - didn't you
> get *any* of the
> responses?
>
> Once again for the record:
>
> long a = 5;
> float b = a/255L;
>
> Assignment (=) has a lower precedence than division
> (/), so the
> division is performed first. Both 5 and 255L are
> longs, so no
> conversion is necessary and an integer division is
> performed, with a
> result of 0.
>
> After the division is complete, the assignment takes
> place; at that
> point a conversion is necessary to convert the
> integer result on the
> right-hand side of the assignment so it can be
> stored in the float
> variable on the left-hand side.
>
> What you need to do is force the division to be done
> with floats; the
> easiest way is to use a float constant:
>
> float b = a/255.0;
>
> You could also typecast one or both of the arguments
> to the division:
>
> float b = (float)a/255L;
>
> sherm--
>
> Cocoa programming in Perl:
> http://camelbones.sourceforge.net
> Hire me! My resume: http://www.dot-app.org
>
>
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