NSXML and DTD
NSXML and DTD
- Subject: NSXML and DTD
- From: Niels Meersschaert <email@hidden>
- Date: Fri, 8 Sep 2006 15:47:17 -0400
I'm trying to validate an xml document against an external DTD on
Tiger. I need to be able to validate it against a given external
DTD, whether or not the source xml declares the same DTD. What I've
tried is this:
Construct a new DTD
NSXMLDTD *newDTD = [[NSXMLDTD alloc] initWithContentsOfURL:dtdPath
options:nil error:nil];
[xml setDTD:newDTD];
If I print out the xml document as it currently exists using
NSLog(@"Document now looks like:\n%@",[xml
XMLStringWithOptions:NSXMLNodePrettyPrint]);
I see a Doctype declaration with all the elements in my original
source DTD at the dtdPath. However, there isn't a root element
declared:
<!DOCTYPE [
<!ELEMENT foo (bar)*>
<!ELEMENT bar (#PCDATA)>
]>
<foo>
<bar>Stuff</bar>
<bar>More stuff</bar>
</foo>
If I try to validate it using [xml validateAndReturnError:&error]; I
get an error:
xml failed validation: NSError "no DTD found!
" Domain=NSXMLParserErrorDomain Code=1 UserInfo=
{NSLocalizedDescription = "no DTD found!\n"; }
I think it needs to have the root element defined such that the xml
looks like:
<!DOCTYPE foo [
<!ELEMENT foo (bar)*>
<!ELEMENT bar (#PCDATA)>
]>
<foo>
<bar>Stuff</bar>
<bar>More stuff</bar>
</foo>
How do I set the root element in the doctype? I see no methods for
this in either the NSXMLDTD or NSXMLDocument classes. Am I missing
something?
Thanks,
Niels
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