Re: Calculating the size of NSFont...
Re: Calculating the size of NSFont...
- Subject: Re: Calculating the size of NSFont...
- From: Buddy Kurz <email@hidden>
- Date: Sun, 4 Mar 2007 08:03:28 -0800
Are you keeping everything in floats?
I use the following code snippet in a terminal emulator to get a font
size that matches an integral 'box' size
float trialSize;
int deltaX; //width of cell
trialSize=72;
trialFont = [manager fontWithFamily:fontFamily
traits:NSFixedPitchFontMask weight:7 size:trialSize];
trialSize = ((trialSize * deltaX) / ([trialFont
widthOfString:@"W1234"]/5));
trialFont = [manager fontWithFamily:fontFamily
traits:NSFixedPitchFontMask weight:7 size:trialSize];
like your signature...
buddy kurz
On Mar 3, 2007, at 10:52 PM, Rachel Blackman wrote:
Alright, one more query, as long as I'm diving back into the
cocoadev folder... :)
I've got a monospaced font. I need to calculate the 'width' of a
given character, so that I can figure out certain things. However,
I can't seem to quite get a 'right' value. If I draw a bunch of
boxes and start typing, the characters and the boxes get out of
alignment after a while.
NSFont -maximumAdvancement seems to have the boxes ever so slightly
too small, which isn't surprising; I think -maximumAdvancement
isn't actually accounting for space between the characters. Taking
a string of characters, figuring out the size using NSFont -
widthOfString: and then dividing by the string length gets me
closer (and 'good enough' for some purposes) but still gets offset
after about 20 characters. So, also no good for this particular
case, where I need the alignment good for up to about 90 characters.
Given that I have turned off kerning on the textview where this
would be displayed, Is there some relatively simple way I'm missing
to get what the spacing is between the characters, some nice value
to add to -maximumAdvancement?
--
Rachel 'Sparks' Blackman -- sysadmin, developer, mad scientist
"If it is not broken, give me five minutes to redesign it!"
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