Thank you Robert and Amritendu, now I understand.
I have one more question. In the same code there is
// Standard accessors
- (Track *)track
{
return [[track retain] autorelease];
}
Why not just
// Standard accessors
- (Track *)track
{
return track;
}
Bob
----- Original Message ----
From: Robert Cerny <email@hidden>
To: Bob Ueland <email@hidden>
Cc: email@hidden
Sent: Monday, October 15, 2007 10:27:39 AM
Subject: Re: Simple dealloc question
Hi Bob,
you're right, it's completely sufficient to release track object.
However, setting it to nil helps tracking possible bugs in your code,
because you will immediately see in the debugger that you are sending
messages to nil object.
HTH
Robert
On 15.10.2007, at 9:58, Bob Ueland wrote:
Found the following code in an example (track is a pointer to a
Track object)
- (void)dealloc
{
[track release], track = nil;
[super dealloc];
}
What is the point of having track = nil? Wouldn't the following
code be enough?
- (void)dealloc
{
[track release];
[super dealloc];
}
Bob
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