Re: Simple NSMutableDictionary problem
Re: Simple NSMutableDictionary problem
- Subject: Re: Simple NSMutableDictionary problem
- From: Mark Allan <email@hidden>
- Date: Tue, 12 Aug 2008 22:16:23 +0100
At 9:12 pm +0000 12/08/2008, Matt Keyes wrote:
How do I have an int as a value in a NSMutableDictionary object?
for example:
NSMutableDictionary *myDictionary = [NSMutableDictionary alloc];
int i = 1;
[myDictionary setValue:1 forKey:@"One"];
This causes a compiler warning:
"warning: passing argument 1 of 'setValue:forKey:' makes pointer
from integer without a cast"
It seems like (b/c the type is "id" for the first param) that
NSMutableDictionary wants a pointer. Well, how do I give it just a
plain integer copy without having the compiler yell at me? I have
been banging my head on my desk over this silly little thing.
Also, how do I define a non-mutable dictionary of a particular size?
There is no dictionaryWithCapacity function that I can find in the
non-mutable version. All the examples I can find are not practical
(i.e. hardcoding a dictionary at its creation with random values
like @"One", @"Two", etc.).
Thanks!
Matt
You need to pass it an NSNumber. Do something like this:
[myDictionary setObject:[NSNumber numberWithInt:1] forKey:@"one"];
Mark
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