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Re: Reversing a String
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Re: Reversing a String


  • Subject: Re: Reversing a String
  • From: "Adam R. Maxwell" <email@hidden>
  • Date: Tue, 30 Dec 2008 21:59:00 -0800


On Dec 31, 2008, at 4:23 PM, Ron Fleckner wrote:
	const int stringLength = [aString length];
	char reverseChars[stringLength];
	for (i = stringLength - 1, j = 0; i >= 0; i--, j++)
	{
		char c = [aString characterAtIndex:i];
		reverseChars[j] = c;
	}

Unfortunately, this is not correct; -[NSString characterAtIndex:] returns a unichar, which is not a char. In addition, it will give odd results for composed characters. Depending on what you want, you might be able to use rangeOfComposedCharacterAtIndex:.


I'd also use NSMutableString instead of a stack buffer of chars, since this looks like a buffer overflow (unless I'm missing something):

reverseChars[j] = '\0';// create a C (UTF8) string by adding a null char


--
Adam

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  • Follow-Ups:
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References: 
 >Reversing a String (From: "Gabe Shahbazian" <email@hidden>)
 >Re: Reversing a String (From: Ron Fleckner <email@hidden>)

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