Re: Why can't I name a property `tag'?
Re: Why can't I name a property `tag'?
- Subject: Re: Why can't I name a property `tag'?
- From: an0 <email@hidden>
- Date: Thu, 10 Jul 2008 23:19:16 +0800
I admit it is my fault if you don't know what exact type of Cocoa I
am, since I don't tell you. So it is reasonable for you to just call
me Cocoa.
However, if you don't know what exact type of Cocoa I am, how could
you call me BlackCocoa so surely?
On Thu, Jul 10, 2008 at 10:57 PM, Jean-Daniel Dupas
<email@hidden> wrote:
> You don't say you "my pet", you said "one of my family member's pet"
> I'm not wrong if I assume that it's your brother pet.
>
> Just tell the compiler it is your pet and not your brother's on and it will
> be happy (see the cast in the following line):
>
>
> filteredPosts = [[self filterPosts:postNodes WithTag:[(Foo *)[tagView
> itemAtRow:row] tag]] retain]
>
>
> Le 10 juil. 08 à 16:50, an0 a écrit :
>
>> We are Cocoa family. I am a RedCocoa, and my elder brother is a
>> BlackCocoa. We both have a `pet', but our Dad doesn't. My pet is a
>> Cat, while my elder brother's pet is a Dog. And of course he got his
>> pet long before me, for he is 10 but I am only 2. So as a Cocoa, am I
>> supposed to have a pet Dog just because my elder brother has one? And
>> should I be accused of lying every time I say I have a pet Cat?
>>
>> On Thu, Jul 10, 2008 at 10:10 PM, I. Savant <email@hidden>
>> wrote:
>>>
>>> On Thu, Jul 10, 2008 at 9:49 AM, an0 <email@hidden> wrote:
>>>>
>>>> Thanks. But isn't it annoying for XCode to pretend to know something
>>>> for sure while in fact it is just a wrong guess? At least the warning
>>>> is very misleading.
>>>
>>> How is this XCode's fault, exactly? You appear to be blaming the IDE
>>> for the idiosyncrasies of a dynamically-typed language combined with
>>> your own lack of specificity. We'll leave alone the fact that XCode !=
>>> gcc ...
>>>
>>> As far as the warning goes, it isn't misleading at all - it's
>>> telling you exactly what's happening. That it's "alright" in this case
>>> can't be known by anybody but the developer with the information the
>>> compiler has (unspecific type).
>>>
>>> --
>>> I.S.
>>>
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