Re: sorting two arrays
Re: sorting two arrays
- Subject: Re: sorting two arrays
- From: William Squires <email@hidden>
- Date: Mon, 28 Jul 2008 19:16:28 -0500
The most logical is to make a class that has - as properties - the
two pieces of data being sorted, then put these in an NSArray (or
NSMutableArray as appropriate to your situation), and then sort that
instead. Not only will it sort both pieces of data together, but it's
a lot easier to extend if you need more data sorted along with the
key array.
So if array1 is an array of 'int', and array2 is an array of
'NSString *', then you would make a class like:
@interface sortableData : NSObject
{
int sortKey;
NSString *data;
}
// useful methods here...
@end
then - in your .m file - implement a sort method that takes an
'NSArray *' pointing to the array filled with references to
sortableData objects. Now, when you sort it, all the other data (the
NSStrings) come along for the ride for free.
The other way to do it is - when you do a swap() on one array's
elements i and j, you swap the elements i and j of (all) the other
array(s) related to the key value array (the one you're directly
sorting on.)
Finally, put the data into a database with an SQL front-end, and
do the sort that way.
That said, I hope you get it working. :)
On Jul 28, 2008, at 10:08 AM, Jeff LaMarche wrote:
Hey all...
I've got two arrays that are related, so that object 0 in one array
corresponds to object 0 in the other array. I'd like to implement a
sort based on the values in one array, but to reorder both array
so that the order of the two arrays stays in sync and that object x
in one array continues to correspond to the same thing as object x
in the other array after the sort.
I've got a general idea of how to implement the sort, but since I
know that there are a few places in the system where array pairs
are used like this, I wanted to see if there was any out-of-the-box
way of handling this scenario - I'd hate to reinvent the wheel if
it's not necessary. Does anyone know if there is any easy way to do
this?
TIA,
Jeff
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