RE: In dealloc(): ref @property, Can I use "<property object> = nil; " vs "[<property object> release]; " ?
RE: In dealloc(): ref @property, Can I use "<property object> = nil; " vs "[<property object> release]; " ?
- Subject: RE: In dealloc(): ref @property, Can I use "<property object> = nil; " vs "[<property object> release]; " ?
- From: "Lee, Frederick" <email@hidden>
- Date: Wed, 8 Oct 2008 12:09:12 -0400
- Thread-topic: In dealloc(): ref @property, Can I use "<property object> = nil; " vs "[<property object> release]; " ?
I've been setting my property thusly:
@property (nonatomic, retain) myVar;
...what about:
@property (nonatomic, copy) myVar; ?
Ric.
From: Ron Lue-Sang [mailto:email@hidden]
Sent: Wednesday, October 08, 2008 11:06 AM
To: Lee, Frederick
Cc: email@hidden
Subject: Re: In dealloc(): ref @property, Can I use "<property object> =
nil; " vs "[<property object> release]; " ?
On Oct 8, 2008, at 8:49 AM, Lee, Frederick wrote:
Assuming the following:
@property(retain) myVar;
...
@synthesize myVar;
...
-(void) dealloc {
// Can I use:
self.myVar = nil;
// versus:
[myVar release]; // ?
}
I've seen examples of using [myVar release]. But doesn't setting myVar
= nil does the same thing?
Which is the preferred way?
I prefer doing [myVar release]. Mainly because I don't want setMyVar
getting called during dealloc. And by this time there *shouldn't* be any
KVO observers for myVar (assuming the property was observed at all
before).
Yea yea - you've done @synthesize here so we know that the setter
doesn't do any custom work. But since we're in dealloc, we are -
obviously - not running under GC. Under refcounting, if you didn't
declare your property nonatomic, you're gonna take a lock during dealloc
to do setMyVar:nil.
--------------------------
RONZILLA
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