Re: showing window causes EXC_BAD_ACCESS
Re: showing window causes EXC_BAD_ACCESS
- Subject: Re: showing window causes EXC_BAD_ACCESS
- From: Daniel Child <email@hidden>
- Date: Fri, 26 Sep 2008 14:45:13 -0400
I should? Then how do I get the reference back? If windowA is a window
outlet in my AppController, then first time around I don't do
anything. It is automatically assigned a reference when the window
loads, and I can use makeKeyAndOrderFront.
But if I choose to automatically release the window on closing, how do
I get the variable windowA reassigned to the window? I don't want to
reload the entire nib because there may be other things in the nib
that don't need to be reloaded....
On Sep 26, 2008, at 1:33 PM, email@hidden wrote:
Message: 1
Date: Fri, 26 Sep 2008 10:34:50 -0500
From: Scott Ribe <email@hidden>
Subject: Re: showing window causes EXC_BAD_ACCESS
To: Michael Ash <email@hidden>, Cocoa Developers
<email@hidden>
Message-ID: <C5026B4A.A4034%email@hidden>
Content-Type: text/plain; charset="US-ASCII"
I can't think of a single reasonable use case for it
An app with many windows, many of which can display multiple
instances at a
time--they should be released when closed.
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