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Re: Core Data debugging
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Re: Core Data debugging


  • Subject: Re: Core Data debugging
  • From: Quincey Morris <email@hidden>
  • Date: Thu, 16 Jul 2009 16:16:30 -0700

On Jul 16, 2009, at 15:54, Quincey Morris wrote:

On Jul 16, 2009, at 15:19, Timothy Wood wrote:

then at "xxx" you'd like to build a new NSError that has *outError (if outError != NULL) as the underlying error....

It seems to be you have this precisely upside-down. outError is an output parameter, not an an input-output parameter. There *is* no input value of *outError that can become the underlying error.

Well, I did misunderstand, by not reading carefully enough. But I'd still be interested to see an example of the code with the macro in place. Is 'outError' a parameter to the macro at xxx? If so, why wouldn't you just pass nil as the parameter at yyy?



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  • Follow-Ups:
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References: 
 >Re: Core Data debugging (From: email@hidden)
 >Re: Core Data debugging (From: Fritz Anderson <email@hidden>)
 >Re: Core Data debugging (From: BJ Homer <email@hidden>)
 >Re: Core Data debugging (From: Bill Bumgarner <email@hidden>)
 >Re: Core Data debugging (From: Kyle Sluder <email@hidden>)
 >Re: Core Data debugging (From: Bill Bumgarner <email@hidden>)
 >Re: Core Data debugging (From: Timothy Wood <email@hidden>)
 >Re: Core Data debugging (From: Quincey Morris <email@hidden>)

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