Re: NSImage and NSBitmapImageRep
Re: NSImage and NSBitmapImageRep
- Subject: Re: NSImage and NSBitmapImageRep
- From: Ken Ferry <email@hidden>
- Date: Tue, 16 Mar 2010 23:52:37 -0700
You'd add an NSBitmapImageRep to an NSImage with -[NSImage
addRepresentation:].
However, an NSImage is not going to be any easier to draw rotated than an
NSBitmapImageRep. You can draw rotated by changing the coordinate system
right before you draw your image, drawing, and putting it back.
See NSAffineTransform<http://developer.apple.com/mac/library/DOCUMENTATION/Cocoa/Reference/Foundation/Classes/NSAffineTransform_Class/Reference/Reference.html>and
the Cocoa
Drawing Guide<http://developer.apple.com/mac/library/DOCUMENTATION/Cocoa/Conceptual/CocoaDrawingGuide/Introduction/Introduction.html>
.
-Ken
On Tue, Mar 16, 2010 at 11:39 PM, Martin Beroiz <email@hidden>wrote:
> Hello everybody,
>
> I have a question relating NSImage and NSBitmapImageRep. I have a stream of
> data that I want to display in a view and it's not in any standard image
> format. So I created an NSBitmapImageRep, then I filled the bitmapdata with
> the data and drew it in the view with drawInRect: method of
> NSBitmapImageRep. All that works perfect.
> Now I want to rotate the image 90 degrees before I draw it but without
> changing the view's coordinate system because i need to draw other things on
> it. So I thought of making my bitmap rep into an NSImage.
>
> Question is how. I read the docs but they I cannot understand exactly what
> is the relation between an NSImage and NSBitmapImageRep.
> From the docs:
>
> "Image representations are used by an NSImage object to manage image data."
>
> "If you are creating images dynamically, you are responsible for creating
> the image representation objects you need for your image."
>
> I don't see how you'd "hook" an image with a bitmap rep or vice-versa.
> The only relevant method of NSImage I found is drawRepresentation:inRect:
> but the docs say that I shouldn't call this method directly.
>
> So how would you guys do this?
>
> Thanks
> Martin.
>
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