Re: sizeof a function
Re: sizeof a function
- Subject: Re: sizeof a function
- From: Kyle Sluder <email@hidden>
- Date: Tue, 9 Nov 2010 02:07:47 -0800
On Mon, Nov 8, 2010 at 9:06 AM, Gerriet M. Denkmann <email@hidden>
wrote:
> typedef char *(*my_type)(const char *, int);
> my_type some = index;
> fprintf(stderr,"sizeof(index): %lu\n", sizeof(index));
> fprintf(stderr,"sizeof(some): %lu\n", sizeof(some));
1. This is not a Cocoa question.
2. sizeof of an expression of function type is illegal according to
constraint 1 of section 6.5.3.4 of C99:
http://www.open-std.org/jtc1/sc22/WG14/www/docs/n1256.pdf
--Kyle Sluder
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