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Re: protocol and properties
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Re: protocol and properties


  • Subject: Re: protocol and properties
  • From: "Stephen J. Butler" <email@hidden>
  • Date: Sun, 28 Nov 2010 02:50:25 -0600

On Sun, Nov 28, 2010 at 2:15 AM, Martin Hewitson
<email@hidden> wrote:
> Suppose I have a formal protocol which defines a method:
>
> - (NSArray*)objects;
>
> Then I implement a class which implements this protocol. To do that I make a property:
>
> @property (nonatomic, readwrite, retain) NSArray * objects;
>
> and put the appropriate synthesize statement in the implementation.
>
> I get compiler warnings that this class doesn't implement the protocol. It seems it doesn't take the synthesized getter as being an implementation of the -objects method.
>
> I also tried explicitly adding the implementation, but the warning remains:
>
> - (NSArray*) objects
> {
>  return objects;
> }
>
> Am I doing something wrong here, or is it not possible to use a property to satisfy a protocol?

Works for me:


#import <Foundation/Foundation.h>

@protocol Bar
- (NSArray*) objects;
@end

@interface Foo : NSObject < Bar > {
    NSArray *objects;
}
@property (nonatomic, readwrite, retain) NSArray *objects;
@end

@implementation Foo
#if 0
- (NSArray*) objects { return objects; }
- (void) setObjects:(NSArray*)o {
    [o retain];
    [objects autorelease];
    objects = o;
}
#else
@synthesize objects;
#endif
@end

int main (int argc, const char * argv[]) {
    NSAutoreleasePool * pool = [[NSAutoreleasePool alloc] init];

    Foo *f = [[[Foo alloc] init] autorelease];
    id< Bar > b = f;

    f.objects = [NSArray arrayWithObjects:@"one",
                 @"two", @"three", nil];
    NSLog( @"objects = %@", [b objects] );

    [pool drain];
    return 0;
}
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