Re: Not understanding NSString's compare:options:range:locale: method
Re: Not understanding NSString's compare:options:range:locale: method
- Subject: Re: Not understanding NSString's compare:options:range:locale: method
- From: "Stephen J. Butler" <email@hidden>
- Date: Fri, 8 Oct 2010 13:40:26 -0500
On Tue, Oct 5, 2010 at 4:48 AM, Derek Huby <email@hidden> wrote:
> This method isn't doing what I expect it to do (which probably means that I'm expecting the wrong thing.)
>
> //=====================================================
> NSRange range = NSMakeRange(0,1);
>
> NSString *s1 = @"ab";
> NSString *s2 = @"ac";
>
> //Just compare the first character
> NSComparisonResult result1 = [s1 compare:s2 options:NSLiteralSearch range:range locale:[NSLocale currentLocale]];
> NSLog(@"Result 1 = %d", result1);
>
> //Now swap the order of the strings
> NSComparisonResult result2 = [s2 compare:s1 options:NSLiteralSearch range:range locale:[NSLocale currentLocale]];
> NSLog(@"Result 2 = %d", result2);
> //=====================================================
>
> I get a result of -1 both times. Since we are only comparing the first character, shouldn't the result be 0?
>From the docs:
range
The range of the receiver over which to perform the comparison. The
range must not exceed the bounds of the receiver.
So you are comparing @"a" to @"ac" in the first case, and @"a" to
@"ab" in the second.
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