Re: NSString "midstring()"
Re: NSString "midstring()"
- Subject: Re: NSString "midstring()"
- From: Quincey Morris <email@hidden>
- Date: Sun, 17 Apr 2011 13:50:44 -0700
On Apr 17, 2011, at 13:09, JAMES ROGERS wrote:
> char sndBuffer[65];
> int j;
>
> characterIndex++; // is always sitting at the last character sent so advance to the next character in string.
> for (j = 0; j < 65; j++) {
> sndBuffer[j] = [string characterAtIndex:characterIndex];
> characterIndex++;
> }
> sndBuffer[j] = 0x00;
> substring = [NSString stringWithUTF8String:sndBuffer];
>
> It works flawlessly, but there oughta be a way without reverting to C?
This code is just wrong, BTW.
The return value from -[NSString characterAtIndex:] is 'unichar', which is a 16-bit quantity, so assigning it to a 'char' variable isn't a good idea.
Also, the return value is *not* a character, in the sense of being a Unicode code point. It's an element of the UTF-16 representation of the string. That means you can't just stop extracting elements at an arbitrary position, without potentially breaking the current substring and/or the next substring.
Either you're going to have to analyze the sequence of elements manually according to the UTF-16 definition to find a good break point, or use something like -[NSString rangeOfComposedCharacterSequence...] (which doesn't do the same thing, but does guarantees a usable UTF-16 break point).
Also, re-creating the NSString (substring) using a UTF-16 string but pretending it's a UTF-8 string isn't going to work very well.
Also, it matters what's going to happen to your substring next. The UTF-8, UTF-16 and Unicode code point byte-lengths of a string are all different, so your assumptions about what fits into a fixed-size buffer need to be carefully re-examined.
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