Re: dispatch queue as property
Re: dispatch queue as property
- Subject: Re: dispatch queue as property
- From: Jamie Pinkham <email@hidden>
- Date: Wed, 02 Nov 2011 09:11:48 -0400
Bruno,
> @property (nonatomic, retain) dispatch_queue_t *dispatchQueue;
Let's assume for a second that this worked. Since dispatch_queue_t is already typedef'd as a pointer "typedef struct dispatch_queue_s *dispatch_queue_t;". You've declared the property as a pointer to a pointer, which means that he would have to dereference that pointer in his class that has the property, every time he uses it.
Secondly, dispatch_queue_t doesn't subclass NSObject, or implement the NSObject protocol, and therefore doesn't implement the -[retain] message. The auto-generated getter and setter would crash.
-Jamie
EDIT: re-sent to list.
On Nov 2, 2011, at 8:02 AM, Bruno Berisso wrote:
> Hi Andreas.
>
> I assuming that you aren't using ARC, right?
> Be aware that the property declaration that you send doesn't retain anything. The declaration should by:
>
> @property (nonatomic, retain) dispatch_queue_t *dispatchQueue;
>
> On Nov 2, 2011, at 9:52 AM, Andreas Grosam wrote:
>
>> I want to set a dispatch queue via a property. How should I set the property's attributes when the queue is retained/released via functions dispatch_retain() and dispatch_release()?
>>
>> Currently, since using "retain" is only possible for objects, I just declare it like follows:
>>
>> @property (nonatomic) dispatch_queue_t dispatchQueue;
>>
>>
>> But here, the retain/release semantic isn't exposed. Any better ideas?
>>
>>
>>
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