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Re: Best way to parse a time today?
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Re: Best way to parse a time today?


  • Subject: Re: Best way to parse a time today?
  • From: Tom Hohensee <email@hidden>
  • Date: Thu, 13 Oct 2011 07:34:04 -0500

I use the same approach the Roger pointed out  and have not encountered any problems as well.  However, I not only set the time but the date (month, day, year) as well.  The DST boundries should not matter since I am decomposing today's date [NSDate date],  which is set by the end user's time settings in system preferences.  Is this not correct?

Thanks.

Tom

On Oct 12, 2011, at 9:01 PM, Roger Dalal wrote:

> Dave:
>
> Would it be possible for you to present an improved approach, please? I use this solution frequently, and have not yet encountered any issues, but now you have me worried! What approach do you suggest?
>
> Roger Dalal
>
>
> On Oct 12, 2011, at 9:49 PM, Dave DeLong wrote:
>
>> Be careful with this approach, since there are some weird edge cases where that time may not exist on the proposed day (think DST boundaries).
>>
>> Dave
>>
>> Sent from my iPhone
>>
>> On Oct 12, 2011, at 6:46 PM, Roger Dalal <email@hidden> wrote:
>>
>>> Rick:
>>>
>>> The following code, which is likely what you are doing, will return the time in 1970 (NSDate's reference date) because you have not specified a date:
>>>
>>> NSString *timeString = @"14:50 PDT";
>>> NSDateFormatter *df = [[NSDateFormatter alloc ] init];
>>> [df setDateFormat:@"HH':'mm zzz"];
>>> NSDate *date = [df dateFromString:timeString];
>>> [df release];
>>>
>>>
>>> Instead, you need to use date components to set the day as well as the time, per the following:
>>>
>>> NSString *timeString = @"14:50 PDT";
>>> NSDateFormatter *df = [[NSDateFormatter alloc ] init];
>>> [df setDateFormat:@"HH':'mm zzz"];
>>> NSDate *date = [df dateFromString:timeString];
>>>
>>> NSCalendar *calendar = [NSCalendar currentCalendar];
>>> NSDateComponents *dateComponents = [calendar components:( NSYearCalendarUnit | NSMonthCalendarUnit |  NSDayCalendarUnit ) fromDate:[NSDate date]];
>>> NSDateComponents *timeComponents = [calendar components:( NSHourCalendarUnit | NSMinuteCalendarUnit | NSSecondCalendarUnit ) fromDate: date ];
>>>
>>> [dateComponents setHour:[timeComponents hour]];
>>> [dateComponents setMinute:[timeComponents minute]];
>>> [dateComponents setSecond:[timeComponents second]];
>>>
>>> NSDate *timeToday = [calendar dateFromComponents:dateComponents];
>>> [df release];
>>>
>>> Change 'fromDate' in NSDateComponents *dateComponents to whatever date you want in order to create your time on a different day.
>>>
>>> Best Wishes.
>>>
>>> Roger Dalal
>>>
>>>
>>>
>>>
>>> On Oct 12, 2011, at 9:30 PM, Rick Mann wrote:
>>>
>>>> I have a situation where I have to parse times like "14:50 PDT". If I just set up an NSDateFormatter with dateFormat = @"HH:mm z", I end up with a time of day in 1970.
>>>>
>>>> What's the best way to get it to give me that time of day today?
>>>>
>>>> Thanks,
>>>> Rick
>>>>
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  • Follow-Ups:
    • Re: Best way to parse a time today?
      • From: Rick Mann <email@hidden>
References: 
 >Best way to parse a time today? (From: Rick Mann <email@hidden>)
 >Re: Best way to parse a time today? (From: Roger Dalal <email@hidden>)
 >Re: Best way to parse a time today? (From: Dave DeLong <email@hidden>)
 >Re: Best way to parse a time today? (From: Roger Dalal <email@hidden>)

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