Re: __block __weak - am I doing this right?
Re: __block __weak - am I doing this right?
- Subject: Re: __block __weak - am I doing this right?
- From: Fritz Anderson <email@hidden>
- Date: Sat, 18 Feb 2012 11:23:13 -0600
On 18 Feb 2012, at 7:41 AM, steven Hooley wrote:
>> The same issue came up again later the same day:
>>
>> __block UIBackgroundTaskIdentifier bti = [[UIApplication sharedApplication]
>> beginBackgroundTaskWithExpirationHandler: ^{
>> [[UIApplication sharedApplication] endBackgroundTask:bti];
>> }];
>>
>> Without __block, bti is invalid, and you won't find that out easily because it's unlikely that you'll actually expire. :) m.
>
> Can this be right?
If I understand why you're mystified, consider this, without the __block declaration.
- bti starts as junk.
- The block is instantiated, and captures the junk _value_ (because it's not a __block variable) of bti.
- The beginBackgroundTask… method creates the background task identifier.
- That identifier is then assigned to bti. bti is no longer junk, but that does the block no good, because it's already captured the junk value.
If bti is declared __block, the block captures (notionally) a _reference_ to bti. It doesn't evaluate bti until it executes, which will be after the assignment.
— F
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