Re: Desktop geometry problem
Re: Desktop geometry problem
- Subject: Re: Desktop geometry problem
- From: Lee Ann Rucker <email@hidden>
- Date: Fri, 08 Jun 2012 10:51:12 -0700 (PDT)
Searching "bezier path simplify" turned up some interesting results, like this from cocoadev: http://cocoadev.com/wiki/NSBezierPathcombinatorics
Since you have no curves this may be overkill, but I'm sure there's an algorithm out there somewhere for non-intersecting rectangles.
----- Original Message -----
From: "Gregory Weston" <email@hidden>
To: "Kyle Sluder" <email@hidden>
Cc: email@hidden
Sent: Friday, June 8, 2012 4:01:03 AM
Subject: Re: Desktop geometry problem
On Jun 8, 2012, at 02:20, Kyle Sluder wrote:
> On Jun 7, 2012, at 7:30 PM, gweston <email@hidden> wrote:
>
>> On Jun 07, 2012, at 10:22 PM, Graham Cox <email@hidden> wrote:
>>
>>
>> On 07/06/2012, at 9:23 PM, Gregory Weston wrote:
>>
>>> Does anyone know of existing code or a trivial technique to get a CGPath or NSBezierPath that describes the shape of the desktop? I'll write and share it if it's not out there, but I'd rather not reinvent any wheels. My interests are:
>>> 1. It should be the actual perimeter of the desktop, not just the bounding box.
>>> 2. It should be a single polygon, rather than a collection of rectangles.
>>> 3. It should behave properly in the presence of mirrored displays.
>>
>>
>> Just iterate over the list of NSScreens and append each screen rect to a bezier path.
>>
>> First thing I tried. It fails requirement #2.
>
> Is Requirement 2 really a requirement? What are you going to be doing with an NSBezierPath path that is going to be improved by making it a single polygon rather than a union of rectangles?
Strictly what I need is the set of individual line segments that define the perimeter, but I figured that it anyone had a solution to the problem in already it was likely to be giving back a path instead of just a list of points and I could parse the path.
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