Re: Image Colours
Re: Image Colours
- Subject: Re: Image Colours
- From: Alvaro Costa Neto <email@hidden>
- Date: Sat, 03 Mar 2012 12:03:37 -0300
Hi Amy, how are you?
Sounds quite right to me. There is one catch, though: the definition of "dominant color". If you just count the number of pixels with certain colors and grab the top 10, it may not result in what you want. To our eyes, the most dominant color is, usually, the one that has the largest continuous area (blob) in the picture. Think of it like this: if I create a completely noised picture with more blue pixels than red, you won't notice the difference unless the difference itself is significant.
What you may be interested at is something called “region growth”, which returns the continuous regions in the picture and their areas. This may give you better results.
I haven't worked with Quartz Filters, but there may be something there that could help you. Otherwise, grab a region growth algorithm from the web and use it in your code. Just make sure that it will work with you colored pictures (these algorithms are commonly intended to be applied to grayscale images).
I hope that helps.
Abraços,
Alvaro Costa Neto
Em 03/03/2012, às 10:17, Amy Heavey escreveu:
> Hi,
>
> I've got an app that is a custom app for me and my home business, it's not something commercial. It's a core data app and some of the entities have images associated with them. The images themselves are stored separately, and the coredata datastore stores the reference to them.
>
> What I'd like to do if its possible is to analyse the images to find the most dominant colours, then find images with similar colours in them.
>
> I thought I would do this by analysing each image as it is saved and calculate the most common pixel colours, probably by analysing each pixel in the image? and saving the most common colours, perhaps 10 colours. Then I can see what other images have the same colour(s) in.
>
> Does this sound possible at all? I'm a self taught hobby programmer, not an expert at all.
>
> I appreciate any advice or pointers,
>
> Many Thanks,
>
> Amy
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