Re: How to pretty print (big)numbers?
Re: How to pretty print (big)numbers?
- Subject: Re: How to pretty print (big)numbers?
- From: Igor Mozolevsky <email@hidden>
- Date: Sat, 11 Oct 2014 14:03:02 +0100
On 11 October 2014 13:47, Roland King <email@hidden> wrote:
>
> > On 11 Oct 2014, at 8:22 pm, Igor Mozolevsky <email@hidden>
> wrote:
> >
> > On 11 October 2014 07:03, Gerriet M. Denkmann <email@hidden>
> wrote:
> >
> >> On iOS 8.0:
> >>
> >> UInt64 sum = 16494631536958186120UL;
> >> NSString *sumString = [ NSNumberFormatter
> >> localizedStringFromNumber: @(sum)
> >>
> >> numberStyle:
> NSNumberFormatterDecimalStyle
> >> ];
> >> results in sumString = -1,952,112,536,751,365,496, which seems not
> quite
> >> right.
> >>
> >
> >
> > Further thought:- Isn't UInt64 a typedef?
> >
> > Try making the ULL (not UL) number with +(NSNumber
> > *)numberWithUnsignedLongLong method of NSNumber…
> >
>
> I already posted that code (in swift) and it doesn’t work, and it’s
> already been explained why NSNumberFormatter doesn’t work on unsigned long
> longs
>
I'm not on -swift list(s) so can you post it here (or to me) for my benefit?
I tried to locale-print the number in plain C, and it works fine (
http://ideone.com/zqnZqg):-
#include <assert.h>
#include <locale.h>
#include <stdio.h>
#include <stdlib.h>
int main(void) {
char *numstr;
int out_len;
unsigned long long num = 1649463153695818612;
setlocale(LC_ALL, "");
const int len = snprintf(NULL, 0, "%'llu", num);
assert(len > 0);
numstr = malloc((size_t) len + 1);
assert(numstr != NULL);
out_len = snprintf(numstr, len + 1, "%'llu", num);
assert(out_len == len && numstr[len] == 0);
printf("%s\n", numstr);
free(numstr);
return 0;
}
Output:-
Success time: 0 memory: 3996 signal:0
1,649,463,153,695,818,612
--
Igor M.
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