Re: NSPredicate or Collection operators?
Re: NSPredicate or Collection operators?
- Subject: Re: NSPredicate or Collection operators?
- From: Sandor Szatmari <email@hidden>
- Date: Mon, 13 Jul 2015 13:27:54 -0400
Why not write it like so...
Sandor Szatmari
> On Jul 13, 2015, at 10:52, Alex Zavatone <email@hidden> wrote:
>
> Ahh, well, it turns out that I had the code right in the first place.
>
> Here it is if anyone needs to do the same thing.
>
> BOOL isItemPresentWithIdenticalValue = NO;
>
> NSArray *allObjects = [self.geofenceObjects allValues];
> NSArray *allOccurrencesOfSourceValue = [allObjects valueForKey:@"smi" ];
>
> isItemPresentWithIdenticalValue = [allOccurrencesOfSourceValue containsObject:thingWeAreCheckingFor]
> ;
BOOL itemIsPresentWithIdenticalValue = [[[self.geofenceObjects allValues] filteredArrayUsingPredicate:[NSPredicate predicateWithFormat:@"smi == %@", thingWeAreCheckingFor]] count] > 0;
That is if all you want to know is 'if an object exists with a value'
(Written in mail, forgive any typos)
>
>
>
>
>
>> On Jul 13, 2015, at 10:35 AM, Alex Zavatone wrote:
>>
>> Hi all. I've got a dictionary of objects that contain properties and need to check if one object has a certain value.
>>
>> I was thinking I could use collection operators and build an array where the value of an an object's property matches that I'm looking for.
>>
>> Then if the array contains that value, we have a match.
>>
>> If each objects in the array has a bunch of properties and one of those properties is called "thing", how would I build an array where the contents of thing would equal a certain value?
>>
>> I'm sure I could walk the array, but I expect there is a more efficient method already built in to Cocoa for this.
>>
>> Thanks in advance.
>>
>> Alex Zavatone
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