Re: Question about enums
Re: Question about enums
- Subject: Re: Question about enums
- From: "Stephen J. Butler" <email@hidden>
- Date: Fri, 17 Jul 2015 15:57:28 -0500
Or what about this? Tested this time...
enum Foo {
case Bar
case Etc
case Etc_Etc
case Custom(String)
func asString() -> String {
switch self {
case .Bar: return "Bar"
case .Etc: return "Etc"
case .Etc_Etc: return "Etc Etc"
case .Custom(let value): return value
}
}
init(withString value: String) {
switch value {
case "Bar": self = .Bar
case "Etc": self = .Etc
case "Etc Etc": self = .Etc_Etc
default:
self = .Custom(value)
}
}
}
let a = Foo(withString: "Bar")
let b = Foo(withString: "Something Else")
print("a = \(a.asString()); b = \(b.asString())")
I guess more typing, and some room for error in the initializer, but it
does do away with the wrapper class.
On Fri, Jul 17, 2015 at 3:39 PM, Quincey Morris <
email@hidden> wrote:
> On Jul 17, 2015, at 13:33 , Stephen J. Butler <email@hidden>
> wrote:
>
>
> How about using a Custom option with an associated String value?
>
> enum Foo:String {
>
> case Bar = “Bar"
> case Etc = “Etc"
> case Etc_Etc = “Etc Etc"
> case Custom(String)
> }
>
>
> Unfortunately that won’t compile. One alternative is:
>
> enum Foo: String {
> case Bar = "Bar"
> case Etc = "Etc"
> case Etc_Etc = "Etc Etc"
> }
>
> enum FooPlus {
> case AFoo (Foo)
> case AString (String)
>
> var asString: String {
> switch self
> {
> case let .AFoo (foo): return foo.rawValue
> case let.AString (string): return string
> }
> }
> }
>
>
>
>
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