Re: More elegance than a long if/else
Re: More elegance than a long if/else
- Subject: Re: More elegance than a long if/else
- From: Jeff Kelley <email@hidden>
- Date: Fri, 10 Mar 2017 10:54:31 -0500
I realized after sending that 100 won’t be correct, so you’ll need
something like this:
batteryIcon.image = UIImage(named: "\(min(10, (_myBatteryLevel % 10) + 1))")
Jeff Kelley
email@hidden | @SlaunchaMan <https://twitter.com/SlaunchaMan> |
jeffkelley.org
On Fri, Mar 10, 2017 at 10:50 AM, Eric E. Dolecki <email@hidden>
wrote:
> Thank you!
>
> On Fri, Mar 10, 2017 at 10:48 AM Jeff Kelley <email@hidden>
> wrote:
>
>> Something like this should work:
>>
>> batteryIcon.image = UIImage(named: "\((_myBatteryLevel % 10) + 1)")
>>
>>
>> Jeff Kelley
>>
>> email@hidden | @SlaunchaMan <https://twitter.com/SlaunchaMan> |
>> jeffkelley.org
>>
>> On Fri, Mar 10, 2017 at 10:41 AM, Eric E. Dolecki <email@hidden>
>> wrote:
>>
>> I have this super simple code, but I'd like to whittle it down to
>> something
>> a lot smaller - basically looking for multiples of 10 (100-0) for a value.
>> I need coffee, what's a great way to do this in Swift 3?
>>
>> if _myBatteryLevel >= 90 {
>> batteryIcon.image = UIImage(named: "10")
>> } else if _myBatteryLevel >= 80 {
>> batteryIcon.image = UIImage(named: "9")
>> } else if _myBatteryLevel >= 70 {
>> batteryIcon.image = UIImage(named: "8")
>> } else if _myBatteryLevel >= 60 {
>> batteryIcon.image = UIImage(named: "7")
>> } else if _myBatteryLevel >= 50 {
>> batteryIcon.image = UIImage(named: "6")
>> } else if _myBatteryLevel >= 40 {
>> batteryIcon.image = UIImage(named: "5")
>> } else if _myBatteryLevel >= 30 {
>> batteryIcon.image = UIImage(named: "4")
>> } else if _myBatteryLevel >= 20 {
>> batteryIcon.image = UIImage(named: "3")
>> } else if _myBatteryLevel >= 10 {
>> batteryIcon.image = UIImage(named: "2")
>> } else if _myBatteryLevel >= 0 {
>> batteryIcon.image = UIImage(named: "1")
>> }
>>
>> Thanks for thinking about my lame code.
>>
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