16-bit A/D conversion and "calculated" dynamic range of 4.8
16-bit A/D conversion and "calculated" dynamic range of 4.8
- Subject: 16-bit A/D conversion and "calculated" dynamic range of 4.8
- From: Roger Breton <email@hidden>
- Date: Sun, 23 Jul 2006 13:03:13 -0400
I was looking at the specs of the Minolta Dimage 5400 II 35mm slide scanner
today and stumbled on the business of dynamic range again. I know the topic
has been discussed at nauseam here but I could not resist picking you guys
(and gal's) brains for the relationship, if any, that you see between
straight bit depth and dynamic range. I won't debate that a scanner
manufacturer's stated dynamic range claim is to be taken with a grain of
salt, at best. But what I thought was new here, in the Minolta's specs, at
least, is the idea that there is logical relationship that can be devised
between bit depth and dynamic range, that the two can be put into an
equation. So, if I may ask you color gurus out there, how could one work out
such a relationship numerically? I On the one hand, I can understand,
intutively, that as bit depth increases, from, say, 8, 12 to 16, more and
more discrete "levels" of scene brightness can be represented in the
computer. But how can the 4.8 dynamic range figure, which is a logarithmic
representation, I assume, be arrived at and equated with bit depth? 16 bit
is 65,536. Got that. But what real number corresponds to the log of 4.8?
Assuming that this is the log of 4.8 in base 10.
Regards,
Roger Breton | Laval, Canada | email@hidden
http://pages.infinit.net/graxx
_______________________________________________
Do not post admin requests to the list. They will be ignored.
Colorsync-users mailing list (email@hidden)
Help/Unsubscribe/Update your Subscription:
This email sent to email@hidden