Re: 16-bit A/D conversion and "calculated" dynamic range of 4.8
Re: 16-bit A/D conversion and "calculated" dynamic range of 4.8
- Subject: Re: 16-bit A/D conversion and "calculated" dynamic range of 4.8
- From: Roger Breton <email@hidden>
- Date: Sun, 23 Jul 2006 21:25:49 -0400
> It's not the log of 4.8 in base 10. That is the *result* of the calculation.
>
> The 4.8 number is achieved through this equation:
>
> Maximum Density = (log in base 10) of (2 to the power of 16) = 4.816479...
>
> In other words it's the power to which 10 must be raised to obtain the
> equivalent of 65536 (or 2^16).
>
> Regards.
>
> --------------
> Marco Ugolini
Got it Marco: log10 (65536/1) = 4.81...
I can see now why this so-called 'dynamic range' is totally useless
information to help gauge the true ability of a scanner to discriminate
among the darkest tones of an original.
Roger Breton | Laval, Canada | email@hidden
http://pages.infinit.net/graxx
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