Re: Side-chain detection
Re: Side-chain detection
- Subject: Re: Side-chain detection
- From: Stefan Gretscher <email@hidden>
- Date: Wed, 23 Nov 2005 23:27:25 +0100
Am 23.11.2005 um 20:47 schrieb john smith:
Ah, ok, great. So, I guess the solution is this:
1: Don't call GetInput(1) if I only have 1 input bus (I.e. keep track
of my bus count myself).
2: If I have 2 input busses, I can call GetInput(1), which will always
return an object
3: If I have 2 input busses, I can call GetInput(1).IsActive() to
determine whether it's actually "in use" (or "activated" or "has
input" or whatever the proper term is).
Is this correct?
Yes that should do it.
Best,
Stefan
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