RE: audio stream and active channels within said stream
RE: audio stream and active channels within said stream
- Subject: RE: audio stream and active channels within said stream
- From: Philip Lukidis <email@hidden>
- Date: Mon, 12 Sep 2005 10:27:31 -0400
Hi Jeff, I did some experiments, and so far it seems that overriding
addClient() and removeClient() in my IOAudioStream subclass seems to do
the trick, unless I am missing something. I tried to add multiple
clients for several streams, and I get called as expected in
my removeClient() and addClient() members. The tests were done
under Tiger (10.4.2).
Is this not enough? Or am I missing something?
thanks,
Philip Lukidis
-----Original Message-----
From: Jeff Moore [mailto:email@hidden]
Sent: Friday, September 09, 2005 8:40 PM
To: CoreAudio API
Subject: Re: audio stream and active channels within said stream
You can't know which individual channels are in use on a given multi-
channel stream. You can only know which streams are in use.
BTW, finding out which streams are in use should be a matter of just
looking at the buffer sets in the user client object for the engine.
The HAL won't register buffers for streams the process has disabled.
Note that to get access to the buffer set objects in the user-client
object, you have to sub-class the user-client object. I don't think
you have to actually override any methods in the user-client class,
just add a method or two that provides access to the buffer set list.
You also have to over-ride the user-client factory methods in
IOAudioEngine to be sure your user-client object gets used.
Finally, don't forget that there is a user-client object for each
process and you have to examine the buffer sets in all of them to be
sure that a given stream is not currently in used.
On Sep 9, 2005, at 2:41 PM, Philip Lukidis wrote:
> Hi. In my audio kext, assuming that I find a way to know which
> streams are
> active (hopefully by overriding the registering of buffers), how am
> I to
> know how many channels in the activated stream are active? Is
> there a way
> to do this? So far I have not seen this in the source.
--
Jeff Moore
Core Audio
Apple
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