Re: proper way to disconnect AUs
Re: proper way to disconnect AUs
- Subject: Re: proper way to disconnect AUs
- From: William Stewart <email@hidden>
- Date: Thu, 20 Jul 2006 17:47:32 -0700
On 20/07/2006, at 5:36 PM, Karim Morsy wrote:
Hi,
I'm connecting and disconnecting nodes in a running graph. I'm
trying to figure out what's the right way to do so, as I've
experienced some undesired behavior.
Just calling augraph(dis)connect and update does not seem to be
enough. for example, when I add and connect AUTimePitch (and update
the graph) the CPU load increases from 5% to 30%.
when I disconnect the AU, I thought it was no longer processing any
audio data as it has no connections on input or output scope.
however, when I disconnect AUTimePitch the CPU load decreases to
approximately 20% (should be 5% again, if it was really no longer
processing). a bypass on the disconnected AU doesn't change
anything either.
Have you called AUGraphUpdate - disconnect (like connect) will not
take affect until the graph is updated.
The time pitch doesn't do any work outside of its render call, so
once its disconnected it won't do any work.
You can also check on the status of the graph at any time by using
CAShow (myGraph) (CAShow is declared in <AudioToolbox/AudioToolbox.h>
Also, AUNetSend keeps listening for connections even after it's
disconnected.
Yes - because all disconnection does is remove an AU from a render
chain. It doesn't necessarily change the state of the AU. You could
Uninitialise the AU after you've disconnected (and update has done
its work) - then before you reconnect it, just Initialise it again.
Bill
only if I also remove the node (augraphremovenode()) I achieve the
desired result, but I was looking for a way to be able to use a
single instance of the au and keep connecting and disconnecting it
when needed. this does not seem to be possible (is it ?), instead
you have to destroy it and create/initialize a whole new node for
the au again, right ?
does the removenode call both unintialize the AU and close the
component ?
any information on this issue would be appreciated.
thanks,
Karim
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