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Re: Matching Multiple Services?
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Re: Matching Multiple Services?


  • Subject: Re: Matching Multiple Services?
  • From: "Duane Murphy" <email@hidden>
  • Date: Wed, 1 Aug 2007 10:00:49 -0700

--- At Wed, 1 Aug 2007 09:45:10 -0700, Michael Smith wrote:

>
>On Aug 1, 2007, at 9:05 AM, Duane Murphy wrote:
>
>> Thanks Mike, unfortunately, My understanding is that adding multiple
>> items to the dictionary leads to a logical-AND match.
>
>You're correct; my apologies for getting confused on this one.
>
>> That is if I put
>> three different class name match choices into the dictionary, the
>> match
>> will be for all three at once, which of course would match none of
>> the items.
>>
>> Is there some logic that I am missing here?
>
>No; I'm guessing that you're probably stuck with checking several
>times and doing the OR yourself.
>
>Since matching isn't something you would do very often (otherwise,
>you might want to consider using notifications), is there some other
>complication involved, or are you just concerned about cost and
>complexity?

Actually it was for Notifications. I figured it would be more efficient
to use a single OR matching Notification.

Also, I believe you can use OR in a kext by replacing the dictionary
with an array, but i guess that only works for kext. I was hoping there
was an equivalent method available.

I guess I'll just register several notifications.

 ...Duane


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  • Follow-Ups:
    • Re: Matching Multiple Services?
      • From: Michael Smith <email@hidden>
References: 
 >Re: Matching Multiple Services? (From: Michael Smith <email@hidden>)
 >Re: Matching Multiple Services? (From: "Duane Murphy" <email@hidden>)
 >Re: Matching Multiple Services? (From: Michael Smith <email@hidden>)

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