RE: Mac OS X Snow Leopard and 64-bit applications
RE: Mac OS X Snow Leopard and 64-bit applications
- Subject: RE: Mac OS X Snow Leopard and 64-bit applications
- From: Nathan Herring <email@hidden>
- Date: Mon, 31 Aug 2009 23:16:41 +0000
- Thread-topic: Mac OS X Snow Leopard and 64-bit applications
Over here in CLR-land, we've got similar issues where there's no nice autoconf mechanism to figure out what'll get built by gcc if you fail to provide an -arch flag. We use this because we differentiate between building the tools we need to complete the rest of the build, and the actual build products. (The former must run on the current system, even if it's not the exact architecture. i.e., for an x86_64 machine, it can be ppc if Rosetta is installed, or i386. The latter must run for the target system, which might have different minimum/maximum OS requirements.)
If someone comes up with the canonical way to do this, please advise.
-----Original Message-----
From: darwin-dev-bounces+nathanh=email@hidden [mailto:darwin-dev-bounces+nathanh=email@hidden] On Behalf Of Dmitry Markman
Sent: Sunday, August 30, 2009 3:04 PM
To: Mo McRoberts
Cc: email@hidden
Subject: Re: Mac OS X Snow Leopard and 64-bit applications
that's actually exactly the problem for gcc 4.4.1
because config.guess doesn't guess correctly :-)
it returns i386-apple-darwin10.0.0
and configure fails miserably unless I provide host, build and target
arguments explicitly as x86_64-apple-darwin10.0.0
On Aug 30, 2009, at 5:59 PM, Mo McRoberts wrote:
> On Sun, Aug 30, 2009 at 21:26, Brian
> Bechtel<email@hidden> wrote:
>
>> Arch and uname -p both return the processor family type, i386. (as
>> opposed
>> to ppc or arm.) I think the rationale was that too many scripts
>> depend upon
>> this behavior.
>
> This actually doesn't make a huge amount of sense: something like
> config.guess will return 'i386-apple-darwin10.0.1', despite the fact
> that gcc will be (by default) targeting x86_64; anything which relies
> on the knowledge that "i386" is by default entirely 32-bit will
> therefore break. In contrast, most other x86_64 systems tend to be set
> up such that x86_64 is reported as the "system" architecture (where
> the kernel architecture is pretty incidental), and so you have a
> triplet of, say, x86_64-pc-linux-gnu.
>
> I'd be curious to know what would break if uname returned the
> user-space architecture (as targeted by the system compiler by
> default) rather than the kernel architecture.
>
> M.
>
> --
> http://nevali.net
Dmitry Markman
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