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Re: dlsym question

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Re: dlsym question

Subject: Re: dlsym question
From: Peter O'Gorman <email@hidden>
Date: Sat, 09 Apr 2011 14:46:30 -0500

On 04/09/2011 10:04 AM, Shantonu Sen wrote:

What are you really trying to do?
Shantonu
On Apr 9, 2011, at 4:01 AM, Nat! wrote:

I speculate that the problem is, that in i386 the symbol starts with a "." instead of an underscore and that the possibly naive dlsym code gets confused by this.

dlsym looks up C symbols, all of which have a leading underscore, the man page explains this:

The symbol name passed to dlsym() is the name used in C source code. For example to find the address of function foo(), you would pass "foo" as the symbol name. This is unlike the older dyld APIs which required a leading underscore. If you looking up a C++ symbol, you need to use the mangled C++ symbol name.

So, yeah, what Shantonu said.

Peter
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References:  
  >dlsym question (From: Nat! <email@hidden>)
  >Re: dlsym question (From: Shantonu Sen <email@hidden>)




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