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Re: More Java Than WebObjects
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Re: More Java Than WebObjects


  • Subject: Re: More Java Than WebObjects
  • From: "Jonathan Fleming" <email@hidden>
  • Date: Sat, 12 Jun 2004 17:29:55 +0100

From: Daniel Mejia <email@hidden>
To: email@hidden
Subject: Re: More Java Than WebObjects
Date: Sat, 12 Jun 2004 01:08:10 -0500

Why do you want to count the spaces, could no be easier to count only
the commas?
yes but you can't rely on the user to supply the commas... anyhow I've sort of completed the code now, just looking over it and then I'll put it up for everyone

Jonathan :^)


Daniel.




On Jun 12, 2004, at 12:01 AM, email@hidden wrote:

>
> From: Sam Barnum <email@hidden>
> Date: June 11, 2004 2:37:49 PM CDT
> To: WebObjects WebObjects <email@hidden>
> Subject: Re: More Java Than WebObjects
>
>
> You might also take a look at java.io.StreamTokenizer, which has quote
> support built-in. Maybe overkill, but nice to use something that's
> already there.
>
> On Jun 11, 2004, at 9:39 AM, Jonathan Fleming wrote:
>
>>> From: Adam Ramadan <email@hidden>
>>> To: Jonathan Fleming <email@hidden>
>>> Subject: Re: More Java Than WebObjects
>>> Date: Fri, 11 Jun 2004 10:54:35 -0400
>>>
>>> A simple approach would be to add a boolean variable, inQuote, and
>>> use that to track whether or not you're within a quoted phrase. So
>>> asy ou are iterating through the characters and reach a quote you
>>> set inQuote <- !inQuote, and when you reach a whitespace character
>>> you can use the value of inQuote to decide whether to count the
>>> word.
>>
>> What happens if the user has accidently only supplied one open quote
>> and not a closed quote? If I use your approach, which sounded good at
>> first, I'd end up not reading enough spaces therefore having too many
>> words... afterthought: but then I could set the boolean to look for a
>> second quotation mark, else count the spaces... yeah maybe your
>> approach is good afterall, i'll try it.
>>
>> regards
>> Jonathan
>>
>>> For anything more complicated you might want to look at regular
>>> expressions.
>>>
>>> Adam
>>>
>>> Jonathan Fleming wrote:
>>>
>>>> What's the best way to write code that will count the spaces
>>>> between each word but not prases that are sourounded by double
>>>> quotation marks eg. there are 2 phrases in the example below making
>>>> up a total of 6 words (6 spaces), but how can avoid counting the
>>>> spaces in the phrases?:
>>>> walls, plumbing, "painting & decorating", decorating, "concrete
>>>> mixing truck", concreting, bricklayers
>>>>
>>>> This is the code I have so far:
>>>>
>>>> public static String wordCounter(String s, int numOfWords){
>>>> int wordCounter=0;
>>>> int numToReduce=0;
>>>> for (int index=0;index<s.length();index++) {
>>>> char c = s.charAt(index);
>>>> if (Character.isWhitespace(c)) {wordCounter++;} //
>>>> Counts the spaces.
>>>> }
>>>> if (wordCounter > numOfWords) {
>>>> numToReduce=wordCounter - numOfWords;
>>>> throw new NSValidation.ValidationException
>>>> ("You are only allowed to enter "+numOfWords+" words,
>>>> but you have entered "+wordCounter+". <br />"+
>>>> "You'll need to delete any "+numToReduce+" of these
>>>> words.");
>>>> }
>>>> return s;
>>>> }
>>>>
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