Re: AJAX and You backtracked too far error
Re: AJAX and You backtracked too far error
- Subject: Re: AJAX and You backtracked too far error
- From: Ricardo Parada <email@hidden>
- Date: Tue, 15 Nov 2005 17:59:21 -0600
Thanks miguel!
It seems a lot of developers are doing this type of stuff. I got
three really good responses in a couple of minutes.
:-)
On Nov 15, 2005, at 5:44 PM, Miguel Arroz wrote:
Hi!
This is part of the really cool JSON-RPC wrapper component made
by Jean-François Veillette. Just add something like the following
code to the session:
/** If we know the project is using the 'ajax-component' handler,
we should look in the context.request.userInfo dictionary to look
for the 'ajax' key. if the 'ajax' key is there, this indicate an
'ajax' request and we do not want it to have any impact on the page
cache. This method won't call 'super' if the 'ajax' key is
present. */
public void savePage(WOComponent page) {
NSDictionary ui = context().request().userInfo();
if(ui == null || ui.objectForKey
(framework.JSProxyRPC.AJAX_REQUEST_KEY) == null) {
super.savePage(page);
}
}
Of course, you must add the "ajax" key on your request, to
identify it as an AJAX request.
Yours
Miguel Arroz
On 2005/11/15, at 23:36, Ricardo Parada wrote:
I have a little app that displays a page where the user clicks a
hyperlink that invokes a component action that starts a thread of
a long running process.
The page then displays again showing that the task in in-
progress. I then use javascript's XMLHttpRequest to get status
information periodically and update a section of the HTML on the
page to show the user the elapsed time, what it's doing, status
and stuff like that.
The javascript code checks the status of the task until it
completes. When the status is complete I submit the form on the
page to cause it to redisplay. However, when I do that I get this
error:
You backtracked too far.
The application backtracking limit of 30 has been exceeded.
Any ideas how to avoid this error?
The direct action that generates the page with the status
information that is sent to the browser is as follows:
public WOActionResults checkStatusAction() {
return pageWithName("TaskStatus");
}
TaskStatus component simply returns the XML containing the status
information for the running task.
The checkStatusAction is called by the javascript on the browser
using XMLHttpRequest.
I read the WebObjects documentation on page caching but I still
can't figure out how to avoid this error.
If anyone has any ideas please shoot me an email.
Thanks,
Ricardo Parada
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"I felt like putting a bullet between
the eyes of every Panda that wouldn't
scr*w to save its species." -- Fight Club
Miguel Arroz
http://www.ipragma.com
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