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Re: EOOrQualifier generated from an array
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Re: EOOrQualifier generated from an array


  • Subject: Re: EOOrQualifier generated from an array
  • From: Ken Anderson <email@hidden>
  • Date: Mon, 25 Dec 2006 10:24:40 -0500

Clark,

You should look at all the qualifier classes. To do what you're asking, you would do something like this (NOT guaranteed to compile):

NSMutableArray orQualifiers = new NSMutableArray();
Enumeration locationEnum = locations.objectEnumerator();
while (locationEnum.hasMoreElements()) {
Location location = (Location) locationEnum.nextElement();
EOKeyValueQualifier qual = new EOKeyValueQualifier ("LOCATIONKEYPATH", EOQualifier.QualifierOperatorEqual, location);
}
EOOrQualifier orQualifier = new EOOrQualifier(orQualifiers);
EOKeyValueQualifier serialQual = new EOKeyValueQualifier("serialNo", EOQualifier.QualifierOperatorEqual, "SERIALNO");
EOAndQualifier finalQualifier = new EOAndQualifier(new NSArray(new Object[] {serialQual, orQualifier}));


Again, this is from my memory, and I haven't tried to compile it, but hopefully you get the idea. Just create the fetch spec with finalQualifier.

Ken

On Dec 25, 2006, at 2:25 AM, Clark Mueller wrote:

Hello all,

I have a question about fetch specs, and use of arrays as an argument (or not). To me, it seems like intuitive behavior that passing an array as an argument to a fetch spec should generate an "or" qualifier string based on the elements of that array.

Suppose, for example, that I have an entity Inventory and Location. I have a fetch specification for Inventory that looks like "serialNo = $serialNo and location = $location". I would like to be able to pass an array of Locations to this fetch specification, such that a query is created looking like:

select ... from inventory where serialNo = $serialNo and (location=location1 or location=location2 or location=location3)

I'm pretty sure I've seen mention of this behavior before, but I don't quite see how to implement it. Is that something I can use joins for, or is there another way to do it other than manually building the qualifier?

Thanks,
Clark
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