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On Nov 21, 2006, at 3:58 PM, Daniele Corti wrote:

2006/11/21, Fabrice Pipart <email@hidden>:
Hi all !

I have been suprised by the behavior of the EOQualifier and I wonder if it's a bug or just a misunderstanding on my part.
Let's take a simple example (mine was far too complicated to show here) :

Let's say we have the following EO relationships :
Person <--> Employer <--> Company
Person <--> Employee <--> Company

fine, but I would prefer that you use the same name in the sql code ...

Let's suppose I want to fetch the PERSONs that are employers and employees in a given company
Naturally I had a qualifier like this one :

(employee.company = %@) OR (employer.company = %@)

I had troubles with this and then I activated the EOAdaptorDebug
From what I found there, EOF generates the following :
SELECT ... FROM PERSON T0, EMPLOYEE T1, EMPLOYER T2, COMPANY T3
WHERE (T1.COMPANY_FID = ? OR T2.COMPANY_FID = ?) AND T0.ID = T1.PERSON_FID AND T0.ID = T2.PERSON_FID

What is between brackets makes sense obviously and then EOF adds after ANDs all that is necessary to make the relationships right?
But in that case I am looking for someone that is an employer AND an employee ???

I don't think so... T0.ID = T1.PERSON_FID and T0.ID = T2.PERSON_FID
are just a check for consistency, I mean the system must check that person are related with Employee and Employer. and it must be true with AND logic...
It's a bit hard to explane in english...

I might be wrong because I hate SQL but...

I want a person to be an EMPLOYER or an EMPLOYEE, not both

(employee.company = %@) OR (employer.company = %@)

I mean if Bob is an EMPLOYEE (and not an EMPLOYER), how can it match the requirement

T0.ID = T1.PERSON_FID and T0.ID = T2.PERSON_FID

In my personal problem, if I have an object that match (employer.company = %@)

but none that matches (employee.company = %@)

If I just leave (employer.company = %@) in the qualifier I find the object.

If I leave both I don't find it... how come?

I would have prefered to see :
WHERE (T1.COMPANY_FID = ? AND T0.ID = T1.PERSON_FID) OR (T2.COMPANY_FID = ? AND T0.ID = T2.PERSON_FID)

Do I make a mistake ???

I think your code should work too, it would be interesting to try it...
But, the meaning in this context is the same.

bye,
--
Daniele Corti
AIM: S0CR4TE5
Messenger: email@hidden

References:
	>EOQualifier issue (From: Fabrice Pipart <email@hidden>)
	>Re: EOQualifier issue (From: "Daniele Corti" <email@hidden>)