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Re: Duplicating Enterprise Objects
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Re: Duplicating Enterprise Objects


  • Subject: Re: Duplicating Enterprise Objects
  • From: Chuck Hill <email@hidden>
  • Date: Mon, 5 Nov 2007 09:52:03 -0800


On Nov 5, 2007, at 2:41 AM, Stefan Klein wrote:

Hi,

I use the deepCopy method described in "Practical Web Objects" (every WO developer should have one :-) ).

Enumeration relationshipEnumerator = publicRelationships.objectEnumerator();
EORelationship aRelationship;
while (relationshipEnumerator.hasMoreElements()){
aRelationship = (EORelationship) relationshipEnumerator.nextElement();
if (aRelationship.isToMany()) {
// Copy each element of the to-many array
NSArray relatedObjects = (NSArray) original.valueForKey(aRelationship.name());
for (int i = 0, count = relatedObjects.count(); i < count; i++)
...


This work fine if the relationship method is the original generated:
getFoo() { storedValueForKey("foo"); }

But if i override it in the subclass like:
getFoo() {
NSArray array = super.getFoo();
if (array != null && array.count() > 0) {
// hint: _collationArray use EOSortOrdering.sortArrayUsingKeyOrderArray on instances of NSMutableArray
array = _collationArray(array, _Foo.KAUFLAGE + "." + _KAuflage.ORDERBY_KENNZEICHEN);
}
return array;
}


all get messed up.

I'd strongly reccomend NOT doing that. Changing how the EOF methods work is likely to cause all sorts of problems.



To get totally confused if I use:

// Copy each element of the to-many array
NSArray relatedObjects = new NSArray((NSArray) original.valueForKey(aRelationship.name()));
int count = relatedObjects.count();
for (int i = 0; i < count; i++) {
...


in deepCopy the copy semes to be ok.

Can anyone explain why ?

No, I can't think of an explanation for that.

Chuck

--

Practical WebObjects - for developers who want to increase their overall knowledge of WebObjects or who are trying to solve specific problems.
http://www.global-village.net/products/practical_webobjects






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References: 
 >Duplicating Enterprise Objects (From: Stefan Klein <email@hidden>)

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