Re: What is the best way to handle invalid values from a WOTextField?
Re: What is the best way to handle invalid values from a WOTextField?
- Subject: Re: What is the best way to handle invalid values from a WOTextField?
- From: Chuck Hill <email@hidden>
- Date: Tue, 17 Jun 2008 10:32:18 -0700
On Jun 17, 2008, at 10:04 AM, Ralf Schuchardt wrote:
Hi,
in the past (until WO 5.4) I often have used a WOTextField with a
formatter to prevent errors like this:
"java.lang.IllegalArgumentException: While trying to invoke the set
method "public void com.cx.harow.eos._ArztFolgedokLeistung
$StorageClass.setAnzahl(java.lang.Short)" on an object of type
com.cx.harow.arzt.dokumente.ArztFolgedokumentationContext
$TempFolgedokLeistung we received an argument of type
java.lang.String. This often happens if you forget to use a
formatter."
When a value was invalid the formatter did not set an invalid value
in my objects.
Now, in WO 5.4 this is no longer true. When the formatter fails to
parse a string it still gets pushed into the target object. As this
is documented is must somehow be considered "expected" behavior.
Unfortunately this breaks all our apps, as no class handles those
invalid strings.
Whoa! Where is this documented? I also depend on this.
Chuck
What is the best way to restore a sane behavior in WO 5.4? Do I have
to write validate...-Methods for every class, that gets formatted
values and drop those strings? Does WONDER have a fix for this?
Thanks,
Ralf
_______________________________________________
Do not post admin requests to the list. They will be ignored.
Webobjects-dev mailing list (email@hidden)
Help/Unsubscribe/Update your Subscription:
This email sent to email@hidden
--
Practical WebObjects - for developers who want to increase their
overall knowledge of WebObjects or who are trying to solve specific
problems.
http://www.global-village.net/products/practical_webobjects
_______________________________________________
Do not post admin requests to the list. They will be ignored.
Webobjects-dev mailing list (email@hidden)
Help/Unsubscribe/Update your Subscription:
This email sent to email@hidden