Re: EOQualifier wildcard problem
Re: EOQualifier wildcard problem
- Subject: Re: EOQualifier wildcard problem
- From: Awbrey Tyler Hughlett <email@hidden>
- Date: Mon, 10 Nov 2008 17:27:25 -0600
On Nov 10, 2008, at 5:20 PM, Ramsey Gurley wrote:
Are you sure this is what isn't working for you? Perhaps a typo?
String cityWildcard = "lub";
NSArray args = new NSArray(cityWildcard + "*");
EOQualifier qual1 = EOQualifier.qualifierWithQualifierFormat("city
caseInsensitiveLike 'lub*'", null);
EOQualifier qual2 = EOQualifier.qualifierWithQualifierFormat("city
caseInsensitiveLike %@", args);
boolean qual1EqQual2 = qual1.equals(qual2);
result: qual1EqQual2 => true
In any case, you should probably be using %s for strings instead of
%@. %@ is for objects, where %s is for strings.
http://developer.apple.com/documentation/DeveloperTools/Reference/WO541Reference/com/webobjects/eocontrol/EOQualifier.html
Ramsey
On Nov 10, 2008, at 4:31 PM, Awbrey Hughlett wrote:
Why does this work for matching the word "Lubbock":
EOQualifier.qualifierWithFormat("city caseInsensitiveLike 'lub*'",
null);
qualifierWithQualifierFormat?
^ The typos were in the mail and not the code. Sorry.
and not this:
String cityWildcard = "lub";
NSArray args = new NSArray(cityWildcard + "*");
EOQualifier.qualifierWithFormat("city caseInsensitiveLike %@",
args);
Am I missing something? I read the webobjects reference documents
on this and they didn't point out the problem. If it makes any
difference, I am using webobjects 5.3 and
Wonder. Can anyone help please?
Thanks,
Awbrey
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I tried it with %s and that didn't help. Lachlan Deck suggested I use
EOKeyValueQualifier() which worked wonders. That should do what I
want, but thanks for the help.
Thanks all,
Awbrey
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