Re: a simple Java question
Re: a simple Java question
- Subject: Re: a simple Java question
- From: Farrukh Ijaz <email@hidden>
- Date: Tue, 4 Jan 2011 15:01:35 +0300
Hi Ted,
You should use only estimates().
if(estimates()) {
// your code.
}
jobIsClosed() || !jobIsClosed() will always return true as at one given moment one of them will be true so anding it to estimates() doesn't make sense as if estimates() is false the evaluation will quit with false due to java precedence which is left to right.
Farrukh
On 2011-01-04, at 2:51 PM, Theodore Petrosky wrote:
>
>
> if (estimates() && jobIsClosed() || !jobIsClosed()) {}
>
> I have these accessors (estimates() jobIsClosed()). Do I need to parenthesize the second part of this to be correct:
>
> if (estimates() && (jobIsClosed() || !jobIsClosed())) {}
>
>
> the first example is working as I intend, but I originally had:
>
> if (estimates() && jobIsClosed() || estimates() && !jobIsClosed()) {}
>
>
> I was reading and searching on Java precedence and couldn't find anything that specifically answered the question. If I leave my code as the first example, will it come back to bite me later? or is the second example more correct?
>
> Ted
>
>
>
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